how to exit a python script in an if statement

Question

I'm using Python 3.2 and trying to exit it after the user inputs that they don't want to continue, is there code that will exit it in an if statement inside a while loop? I've already tried using exit(), sys.exit(), sys.quit(), quit(), and raise SystemExit.

Answer 1

This works fine for me:

while True:
   answer = input('Do you want to continue?:')
   if answer.lower().startswith("y"):
      print("ok, carry on then")
   elif answer.lower().startswith("n"):
      print("ok, sayonnara")
      exit()

edit: use input in python 3.2 instead of raw_input

Hope it helps!!

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Thanks!

Comments

How do I condition my program to exit?

It usually closes the terminal window by itself after the program.

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Hi @Ceefon, did you try the above mentioned code? It worked fine for me.

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Using Python 3.7.6, I get 'NameError: name 'exit' is not defined'

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Hi, @Nick,

Could you please post your code snippet here, what exactly are you trying to do? It will be helpful for us to resolve it ASAP.

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import sys

# to exit the code

sys.exit()

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Hi, @MDG,

Importing sys will not be enough to make exit live in the global scope.

You either need to do

from sys import exit
exit()

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This worked like dream for what I needed !!!!!!! Thank you!!

Answer 2

Hey All,

Here is my solution to all the above doubt:

To stop code execution in Python you first need to import the sys object. After this you can then call the exit() method to stop the program from running. It is the most reliable, cross-platform way of stopping code execution. Here is a simple example.

1. import sys

2. sys.exit()

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Answer 3

In Python, the break statement provides you with the opportunity to exit out of a loop when an external condition is triggered. You'll put the break statement within the block of code under your loop statement, usually after a conditional if statement.